鲁达 新程序员通常在寻找从函数返回多个值的方法。不幸的是，C和C++不允许直接这样做。但是幸运的是，通过一些巧妙的编程，我们可以轻松实现这一目标。
下面是从C函数中返回多个值的方法：
- 通过使用指针。
- 通过使用结构。
- 通过使用数组。
示例：考虑一个示例，其中的任务是查找两个不同数字中的较大和较小值。 我们可以编写多个函数。主要问题是调用多个函数的麻烦，因为我们需要返回多个值，并且当然要键入更多的代码行。
1）使用指针返回多个值：传递参数及其地址，并使用指针更改其值。
// Modified program using pointers #include <; // add is the short name for address void compare(int a, int b, int* add_great, int* add_small) { if (a > b) { // a is stored in the address pointed // by the pointer variable *add_great *add_great = a; *add_small = b; } else { *add_great = b; *add_small = a; } } // Driver code int main() { int great, small, x, y; printf("Enter two numbers: \n"); scanf("%d%d", &x, &y); // The last two arguments are passed // by giving addresses of memory locations compare(x, y, &great, &small); printf("\nThe greater number is %d and the" "smaller number is %d", great, small); return 0; } 输出：
Enter two numbers: 5 8 The greater number is 8 and the smaller number is 52）使用结构返回多个值：由于结构是用户定义的数据类型。这个想法是用两个整数变量定义一个结构，并将较大和较小的值存储到这些变量中，然后使用该结构的值。
// Modified program using structures #include <; struct greaterSmaller { int greater, smaller; }; typedef struct greaterSmaller Struct; Struct findGreaterSmaller(int a, int b) { Struct s; if (a > b) { s.greater = a; s.smaller = b; } else { s.greater = b; s.smaller = a; } return s; } // Driver code int main() { int x, y; Struct result; printf("Enter two numbers: \n"); scanf("%d%d", &x, &y); // The last two arguments are passed // by giving addresses of memory locations result = findGreaterSmaller(x, y); printf("\nThe greater number is %d and the" "smaller number is %d", re, re); return 0; } 输出：
Enter two numbers: 5 8 The greater number is 8 and the smaller number is 53）使用数组返回多个值（仅当返回的项属于同一类型时有效）：当数组作为参数传递时，其基地址将传递给函数，因此对数组副本所做的任何更改都将在原始数组中更改。
以下是使用数组返回多个值的程序，即在arr[0]存储更大的值，在arr[1]存储较小的值。
// Modified program using array #include <; // Store the greater element at 0th index void findGreaterSmaller(int a, int b, int arr[]) { // Store the greater element at // 0th index of the array if (a > b) { arr[0] = a; arr[1] = b; } else { arr[0] = b; arr[1] = a; } } // Driver code int main() { int x, y; int arr[2]; printf("Enter two numbers: \n"); scanf("%d%d", &x, &y); findGreaterSmaller(x, y, arr); printf("\nThe greater number is %d and the" "smaller number is %d", arr[0], arr[1]); return 0; } 输出：
Enter two numbers: 5 8 The greater number is 8 and the smaller number is 5仅C++方法
1）使用引用返回多个值：我们在C++中使用引用来存储返回的值。
// Modified program using References in C++ #include <; void compare(int a, int b, int &add_great, int &add_small) { if (a > b) { add_great = a; add_small = b; } else { add_great = b; add_small = a; } } // Driver code int main() { int great, small, x, y; printf("Enter two numbers: \n"); scanf("%d%d", &x, &y); // The last two arguments are passed // by giving addresses of memory locations compare(x, y, great, small); printf("\nThe greater number is %d and the" "smaller number is %d", great, small); return 0; } 输出：
Enter two numbers: 5 8 The greater number is 8 and the smaller number is 52）使用Class和Object返回多个值：这个想法类似于结构。我们使用两个整数变量创建一个类，并将较大和较小的值存储到这些变量中，然后使用该结构的值。
// Modified program using class #include <; class GreaterSmaller { public: int greater, smaller; }; GreaterSmaller findGreaterSmaller(int a, int b) { GreaterSmaller s; if (a > b) { s.greater = a; s.smaller = b; } else { s.greater = b; s.smaller = a; } return s; } // Driver code int main() { int x, y; GreaterSmaller result; printf("Enter two numbers: \n"); scanf("%d%d", &x, &y); // The last two arguments are passed // by giving addresses of memory locations result = findGreaterSmaller(x, y); printf("\nThe greater number is %d and the" "smaller number is %d", re, re); return 0; } 输出：
Enter two numbers: 5 8 The greater number is 8 and the smaller number is 53）使用STL元组返回多个值：这个想法类似于结构。我们用两个整数变量创建一个元组并返回该元组，然后在main函数内部，我们使用tie fucntion将值分配给函数返回的min和max。
// Modified program using C++ STL tuple #include<iostream> #include<tuple> using namespace std; tuple <int, int> findGreaterSmaller(int a, int b) { if (a < b) { return make_tuple(a, b); } else { return make_tuple(b, a); } } // Driver code int main() { int x = 5, y= 8; int max, min; tie(min, max) = findGreaterSmaller(x, y); printf("The greater number is %d and the " "smaller number is %d", max, min); return 0; } 输出：
The greater number is 8 and the smaller number is 5